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June 12th, 2007 06:00
SLES 10 and MPIO
Hi all,
As there are some stability issues with Suse SLES 10 and powerpath 5, Dell advised us to use multipath-tools in the meanwhile.
It installed without problems and seems to run very nice, but I still have a question.
The setup is like this: a Dell 1950 with one HBA (qlogic) connected to a CX300.
# multipath -l
3600601602f601a0018907b32cadddb11DGC,RAID 5
[size=80G][features=1 queue_if_no_path][hwhandler=1 emc]
\_ round-robin 0 [prio=0][active]
\_ 1:0:0:0 sdb 8:16 [active][undef]
\_ round-robin 0 [prio=0][enabled]
\_ 1:0:1:0 sdc 8:32 [active][undef]
# multipath -ll
3600601602f601a0018907b32cadddb11DGC,RAID 5
[size=80G][features=1 queue_if_no_path][hwhandler=1 emc]
\_ round-robin 0 [prio=1][active]
\_ 1:0:0:0 sdb 8:16 [active][ready]
\_ round-robin 0 [prio=0][enabled]
\_ 1:0:1:0 sdc 8:32 [active][ready]
When using only one l, it shows 'undef' with the devices. When using double l, it show 'ready'.
Does anybody know what the undef means and does it need to be solved? I searched the internet, but could not find a decent explication on what it means.
Thanks,
Wouter
As there are some stability issues with Suse SLES 10 and powerpath 5, Dell advised us to use multipath-tools in the meanwhile.
It installed without problems and seems to run very nice, but I still have a question.
The setup is like this: a Dell 1950 with one HBA (qlogic) connected to a CX300.
# multipath -l
3600601602f601a0018907b32cadddb11DGC,RAID 5
[size=80G][features=1 queue_if_no_path][hwhandler=1 emc]
\_ round-robin 0 [prio=0][active]
\_ 1:0:0:0 sdb 8:16 [active][undef]
\_ round-robin 0 [prio=0][enabled]
\_ 1:0:1:0 sdc 8:32 [active][undef]
# multipath -ll
3600601602f601a0018907b32cadddb11DGC,RAID 5
[size=80G][features=1 queue_if_no_path][hwhandler=1 emc]
\_ round-robin 0 [prio=1][active]
\_ 1:0:0:0 sdb 8:16 [active][ready]
\_ round-robin 0 [prio=0][enabled]
\_ 1:0:1:0 sdc 8:32 [active][ready]
When using only one l, it shows 'undef' with the devices. When using double l, it show 'ready'.
Does anybody know what the undef means and does it need to be solved? I searched the internet, but could not find a decent explication on what it means.
Thanks,
Wouter
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dynamox
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June 12th, 2007 06:00
i guess -ll option gets information from disk subsystem versus just the kernel ..at least that's how i understand this
Conor
341 Posts
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June 22nd, 2007 01:00
Below is the example from page 26 of a correctly working system:
¿With CLARiiON Logical Unitson a SLES 10 host, the output will look similar to:
# multipath -v2 -d
create: mpath12 (360060160782918000be69f3182b2da11) DGC,RAID 3
[size=3G][features=1 queue_if_no_path][hwhandler=1 emc]
\_ round-robin 0 [prio=2][undef]
\_ 10:0:3:0 sdaq 66:160 [undef][ready]
\_ 11:0:3:0 sdcw 70:64 [undef][ready]
\_ round-robin 0 [prio=0][undef]
\_ 11:0:2:0 sdce 69:32 [undef][ready]
\_ 10:0:2:0 sdy 65:128 [undef][ready]
create: mpath13 (360060160782918004f64715b83b2da11) DGC,RAID 3
[size=3G][features=1 queue_if_no_path][hwhandler=1 emc]
\_ round-robin 0 [prio=2][undef]
\_ 11:0:2:1 sdcf 69:48 [undef][ready]
\_ 10:0:2:1 sdz 65:144 [undef][ready]
\_ round-robin 0 [prio=0][undef]
\_ 10:0:3:1 sdar 66:176 [undef][ready]
\_ 11:0:3:1 sdcx 70:80 [undef][ready]
So, the [undef] flag does not seem to be a problem.
CB