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34 Posts

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April 14th, 2011 14:00

Calculating the Index size of a Client

Hello

I have a NW 7.6 SP1 and I want to know the index size in a client with 50 GB with 475,000 files and a full each Monday, this because I was assigned only 100GB disk for CFI

Regards

2 Intern

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177 Posts

April 15th, 2011 12:00

Allan  -  u r a funny one...!

To add a bit of color from what I know about Allan's stated formula:

- The 160 in the formula is based on a rough assumption of 160 bytes per catalog entry

- The 1.5 is a multiplier for growth/errors which may increase the catalog size (sort of a fudge factor)

I tried my hand at your # of files w/ a 5% data change and a total of 4 of the full cycles maintained (your stats may be completely different on daily change and retention) - but what I'm getting is about 152 MB.

Would be interesting to see what you come out with.  Let us know!

-Eric

334 Posts

April 15th, 2011 12:00

hmmm.. How does that work again.  parenthesis, multiplication, exponents..no, no.. its Please Excuse My Dear Aunt Sally..

Here's the formula you can use to calculate the NetWorker catalog (index) size:

n = number of files to backup

d = days in cycle (time between full backups)

i = incremental data change (i=n * (% data change as a decimal))

c = number of cycles online

CATALOG SIZE = (n+(i*d))*c*160*1.5

Hope this helps.

Allan

25 Posts

August 31st, 2011 04:00

Hello,

If it is true, than what is the right answer for this:

I am prepearing for e20-329 exam...

Consider the following NetWorker environment:


  • 1,000,000 files backed up in a full backup
  • 5% of files changed every day
  • Fulls on Sundays, Incrementals every other day of the week
  • Retention period of four weeks


According to EMC best  practices, approximately how much disk space should the catalog files take in  this environment?

Possible answers are 240GB, 500GB, 1TB, 2TB

My result was cirka 700 MB.....

Zoltan

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