4 Operator

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2.8K Posts

July 1st, 2008 03:00

With a full mesh, the maximum number of switches is bound to the number of ports each switch can offer :D

With full mesh every switch have a direct connection to the other switches.If I have 3 switches, each switch will have at least 1 path to any other switch. This means you have 2 ports on every switch that you are using to form the mash. Obviously the maximum number of switches in a full mash of ds32b2 switches is .. 33 .. thus giving you a huge mesh of .. nothing :D since you are using all ports for ISLs and you have nothing left for hosts/storages. Now it's up to you to scale down and "steal" ISL ports to be used for hosts/storages ;-) .. Less ISLs means more hosts/storages.

You have also options .. if you need more ISLs between any two switches (in case you have a lot of traffic flowing from any two switches) maybe you have to use 2 (or more) ISLs between any two switches, thus cutting in half the maximum number of switches.

In a word.. full mesh is beautyfull but doesn't scale well.

With core/edge the math is simple and plain .... You have a core that will switch traffic between edges and storages. If your core have 64 ports and you need 20 ports for the storages, you have 44 free ports. With core/edge you need thick ISLs (2 or more between each edge and the core) thus giving you 22 edges for your beloved 64 ports core :D

Partial mesh is a subcase of the full mesh .. do your math :D

28 Posts

July 1st, 2008 12:00

Thank you

4 Operator

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5.7K Posts

July 2nd, 2008 00:00

Can you reward Stefano with some points ? He deserves it :)

28 Posts

July 7th, 2008 18:00

I marked it as a correct answer so he must have received the maximum points.....

9 Legend

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20.4K Posts

July 7th, 2008 20:00

Summi ...right next to Stefano's name there is gray button that says "Correct". Please use it to mark his answer.

Thanks

4 Operator

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5.7K Posts

July 8th, 2008 01:00

And you deserve at least 1 helpful for helping out.
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