I've checked all of Excel's help menu's and a number of websites to see if there was a function that would work for my problem, and I can't find any "cookiecutter" solutions. Your suggestion would work if I were comparing differences between two separate lists. Basically, the formula I'm looking for would be something like this:
(Final Entry minus First Entry) divided by (Total Number of Entries minus 1) = Average Difference, or to use my example in the original question -------
(376-150) / (5-1) = 56.5
I just don't know how to write the formula to make it work!
Assuming the values are in column A, the formula picks out the maximum value from the list, subtracts the minimum value, then divides the result by the number of values minus 1.
Perfect! This is EXACTLY what I was looking for. I said that I was new to Excel, but I also knew that it would be a fairly simple formula. I worked it out myself, but I had to add an additional column of values to make it work.
Thanks again, and welcome to the Forum. :smileyvery-happy::smileyvery-happy::smileyvery-happy:
RoHe
10 Elder
•
45.2K Posts
0
August 18th, 2006 23:00
http://www.exceltip.com/st/Calculating_the_Average_Difference_between_List_Price_and_Sale_Price_%09/795.html
Hint: click on spreadsheet on this page which is the link to an expanded sheet showing all the details.
Ron
flgolfnut
71 Posts
0
August 19th, 2006 00:00
RoHe,
I've checked all of Excel's help menu's and a number of websites to see if there was a function that would work for my problem, and I can't find any "cookiecutter" solutions. Your suggestion would work if I were comparing differences between two separate lists. Basically, the formula I'm looking for would be something like this:
(Final Entry minus First Entry) divided by (Total Number of Entries minus 1) = Average Difference, or to use my example in the original question -------
(376-150) / (5-1) = 56.5
I just don't know how to write the formula to make it work!
Art
abach
1.7K Posts
0
August 20th, 2006 12:00
Message Edited by abach on 08-20-200610:05 AM
mpo
2 Intern
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399 Posts
0
August 23rd, 2006 20:00
flgolfnut
71 Posts
0
August 24th, 2006 22:00
mpo,
Perfect! This is EXACTLY what I was looking for. I said that I was new to Excel, but I also knew that it would be a fairly simple formula. I worked it out myself, but I had to add an additional column of values to make it work.
Thanks again, and welcome to the Forum. :smileyvery-happy::smileyvery-happy::smileyvery-happy:
Art